**Find the range of f(x)=cos[x],for x lies between -pi/2 to pi/2**

*Thanks for giving answer to my query but Iwould like to inform that I am not able to understand the solution pls explain it in detail*

__solution given by you earlier__

The given function is f(x)=cos[x],for -pi/2Since the angle is [x] so the interval -pi/2 1. -pi/2 2. -1 3. 0 4. 1 In the interval -pi/2 So, cos [x] = cos(-2) = cos 2In the interval -1 So, cos [x] = cos(-1) = cos 1In the interval 0 So, cos [x] = cos0 = 1In the interval 1 So, cos [x] = cos1Thus, the range of f(x) = cos[x], for -pi/2

f(x)=cos(x)

for x varying between to

the value of cos(x) becomes from 0 to 1

hence range of f(x) for x varying from

to is [0,1]

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